# ? Find¶

Find the first occurrence of an item in a list.

Syntax: x?y, ?[x;y]

where x is a list or a null, returns for

• atom y the smallest index of y
• list y the smallest index of each item of y

Where y or an item of it is not found in x, the smallest index is the smallest integer not found in key x, i.e. count x. Comparisons are exact and are not subject to to comparison tolerance.

q)w:10 -8 3 5 -1 2 3
q)w?-8
1
q)w[1]
-8
q)w?3              / the first occurrence of 3
2
7
q)w[7]
0N
q)"abcde"?"d"
3


## Type-specific¶

Find is type-specific relative to x. Where:

• x is a simple list and y a list whose atoms are all the same type as x, the result corresponds to x item-by-item.


q)rt:(10 5 -1;-8;3 17)
q)i:w?rt
q)i
(0 3 4;1;2 7)
q)w[i]
(10 5 -1;-8;3 0N)


• x is a list of lists and y is a simple list, items of x are matched with the whole of y.


q)u:("abcde";10 2 -6;(2 3;ab))
q)u?10 2 -6
1
q)u?"abcde"
0


• where x is a mixed list then items of x are matched with items of y.


q)u?(2 3;ab)
3 3


In this case Find matches items of x with 2 3 and ab , not (2 3;ab).

## Rank-sensitive¶

x?y can’t deal with mixed-rank x. If rank x is n then x?y looks for objects of rank n-1.

2 3?2 3#til 6  / looks for rank 0 objects
(0 1 2;4 5)?2 3#til 6 / looks for rank 1 objects


A solution to find (2 3;ab) is

q)f:{where x~\:y}
q)f[u;(2 3;ab)]
,2


## Searching tables¶

Where x is a table then y must be a compatible record (dictionary or list) or table. That is, each column of x, paired with the corresponding item of y, must be valid arguments of Find.

q)\l sp.q
q)sp?(s1;p4;200)
3
q)sp?spqty!(s2;p5;450)
12
`